Further readings in BFPSA books, Unit 5, Maintenance course, page 33, issue August 2006.
I found the following:
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Most batteries are designed to be fully discharged over a 20h period.
Design load = C / 20h.
De-rating Factor is:
The alarm load is usually much higher than the stand by load and this high current has to be allowed for in the battery calculation as the de-rating factor.
When the alarm load exceeds the design load then the battery could be considered of highly stressed and de-rating factor should be assumed to be D=2,
Example1:
The design load for a 2Ah battery would be 2Ah/20h = 0.1A
Example2:
The design load for 10Ah battery would be 10Ah/20h = 0.5A
For some systems the alarm load is quite low, perhaps nearly equal to the stand by load. In this case the battery is not stressed and factor D=1. This can make a small reduction to the calculation battery capacity.
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This is quite different to what wiz mentioned about BS version:
My question is:
1 - If the batteries are stressed means: (Alarm load > design load) and (D=2) what equation revealed that?
2 - If the batteries are not stressed means: (Alarm load = stand by load) and D=1 what equation revealed that?
I haven’t got a clue what’s going on in here
Benz, I demand that you read my previous posts again and reconsider your latest comment:
This is quite different to what wiz mentioned about BS version: You will find that much of what I have previously been explaining to you, you have now suddenly uncovered in your BFPSA book. Therefore it certainly is
not quite different.
I would also point out that what I have been trying to get over to you is partly what BS recommends and partly my knowledge of the behaviour of batteries (which is not mentioned,as such, in BS). Both these elements are included in your latest BFPSA quote. Therefore I have previously mentioned every factor you now highlight in the BFPSA advice. You will also note that I have correctly highlighted the BFPSA advice that varies from the BS recommendations. I have even explained why they might use some different calculation figures, but explained that I do not agree that they should give this advice.
You do me a great dishonour by rubbishing my advice.
You seem to have an in-built system of misunderstanding, ignoring, disbelieving anything that I am telling you despite the fact that it is you that has asked for the advice in the first place. I appreciate that I may be poor at putting my points accross, although I have trained dozens of fire alarm engineers over the past 25 years with great success. Therefore I must assume that you either do not read my posts properly or are unable to understand them.
I'm sure you'll understand why I may well, in the future, choose not to join in on any of your posts.
Finally, I would, however make one final comment about the latest BFPSA advice you have quoted as follows:
When the alarm load exceeds the design load then the battery could be considered of highly stressed and de-rating factor should be assumed to be D=2, Please note that the nearest equivalent advice in the BS recommendation quotes a figure of D=1.75 and finally, and most importantly, and as I explained at the very beginning, the BS recommendation is that any specific de-rating factor be obtained from that actual batterys' manufacturer, and in the absence of such, the figures of 1 or 1.75 should be used. BS never mentions the de-rating figure of 2.
In respect of your last two questions, the answers to both is that it is based on the behaviour of batteries to different discharge rates found through experience and testing by the manufacturer. There is probably a precise formula to calculate the behaviour and it will almost certainly include elements of chemical reaction. I do not know this formula. I suggest that you ask a battery manufacturer about it.